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WinForms FAQ - Common Dialogs

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Below is a technique that uses FolderNameEditor and FolderBrowser classes to implement a solution. You can also use iterop to get a solution.

Both the FolderNameEditor and FolderBrowser classes used in this solution are described in the Docs as ‘This type supports the .NET Framework infrastructure and is not intended to be used directly from your code.’

	// add a reference to System.Design.DLL

	using System.Windows.Forms.Design;

	public class DirBrowser : FolderNameEditor
		FolderBrowser fb = new FolderBrowser();

		public string Description
			set { _description = value; }
			get { return _description; }

		public string ReturnPath
			get { return _returnPath; }

		public DirBrowser() { }

		public DialogResult ShowDialog()
			fb.Description = _description;
			fb.StartLocation = FolderBrowserFolder.MyComputer;

			DialogResult r = fb.ShowDialog();
			if (r == DialogResult.OK)
				_returnPath = fb.DirectoryPath;
				_returnPath = String.Empty;

			return r;

		private string _description = 'Choose Directory';
		private string _returnPath = String.Empty;

(Posted by Ryan Farley on the microsoft.public.dotnet.language.csharp newsgroup)

	using System.Text;
	using System.IO;
	private void button1_Click(object sender, System.EventArgs e)
		OpenFileDialog dlg = new OpenFileDialog(); 
		dlg.Title = 'Open text file' ; 
		dlg.InitialDirectory = @'c:\' ; 
		dlg.Filter = 'txt files (*.txt)|*.txt|All files (*.*)|*.*' ; 
		if(dlg.ShowDialog() == DialogResult.OK) 
			StreamReader sr = File.OpenText(dlg.FileName);

			string s = sr.ReadLine();
			StringBuilder sb = new StringBuilder();
			while (s != null)
				s = sr.ReadLine();
			textBox1.Text = sb.ToString();

It is straight-forward. Create an instance of the class and call its ShowDialog method.

	ColorDialog colorDialog1 = new ColorDialog(); 
	//fontDialog1.ShowColor = true; 
	if(colorDialog1.ShowDialog() != DialogResult.Cancel ) 
		textBox1.ForeColor = colorDialog1.Color; 
	textBox1.Text = 'this is a test'; 

It is straight-forward. Create an instance of the class and call its ShowDialog method.

     FontDialog fontDialog1 = new FontDialog(); 
      fontDialog1.ShowColor = true; 
      if(fontDialog1.ShowDialog() != DialogResult.Cancel ) 
           textBox1.Font = fontDialog1.Font ; 
           textBox1.ForeColor = fontDialog1.Color; 
     textBox1.Text = 'this is a test'; 

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