how to pass a file name from current grid row to save the image

Thread ID:	Created:	Updated:	Platform:	Replies:
149285	Nov 20,2019 03:33 PM UTC	Nov 21,2019 05:43 AM UTC	Blazor	2

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Tags: File Upload

Armando Costa

Asked On November 20, 2019 03:38 PM UTC

Using a Grid and a Fileuploader on a column to receive images.

I need the current row "CodArtigo" to be the name of the uploaded file.

...

< GridColumns>

< GridColumn HeaderText="Foto" TextAlign="TextAlign.Center" Width="60" AllowEditing="false">

< Template>

var artigo = (context as Artigos);

< EjsUploader ID="UploadFiles" DropArea=".control-fluid" MaxFileSize=104857600>

< UploaderAsyncSettings SaveUrl="api/Default/Save" RemoveUrl="api/Default/Remove" ChunkSize=500000>

< UploaderEvents FileSelected="@(()=>UpLoadClicked(??? , artigo.CodArtigo))" BeforeRemove="@Remove">< /UploaderEvents>

< /EjsUploader>

< /div>

}

< /Template>

< /GridColumn>

...

void UpLoadClicked(SelectedEventArgs args, ??? string artigo) {

// custom parameter in the selected event

args.CurrentRequest = new List<object> { new { FileName = ????artigo} };

}

How can I do this ?

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Armando Costa

Replied On November 21, 2019 12:34 AM UTC

Never mind ....

Just needed to change

(()=>UpLoadClicked(??? , artigo.CodArtigo)

(args)=>UpLoadClicked(args, artigo.CodArtigo)

sorry for posting

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Saranya Dhayalan [Syncfusion]

Replied On November 21, 2019 05:43 AM UTC

Hi Armando,

Thanks for the update. Please let us know if you need any assistance in Syncfusion product. We are always happy to assist you.

Regards,

Saranya D

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how to pass a file name from current grid row to save the image

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