Just in case anyone was interested, here is the solution:
lChar = Convert.ToInt32(Strings.Mid(sMD5, (lCount * 2) - 1, 2),16) %32;
The key was adding the 16 format specifier.
>I am having a problem converting one line of code in this VB.Net Function.
>I have marked the line below in its context. In the converted C# code I am getting
>a error stating "Input string was not in a correct format". Is there anyone out there
>that can shed some light on fixing this line.. I have included the entire function so
>that you may see the context.
>
>The VB.Net line is : lChar = CInt("&H" & Mid(sMD5, (lCount * 2) - 1, 2)) Mod 32
>
>The Converted C# is : lChar = Convert.ToInt32("&H" + Strings.Mid(sMD5, (lCount * 2) - 1, 2)) % 32;
>
>Thanks for any help sent this way...
>
>Steve Graddy
>
[email protected]
