Get Diagram actual size

[Ivan]

Hi,

how can I get the actual size of my diagram?

For example:

rect = new Rectantle(0,0,20,20);

I want to get the size of the diagram, so, width = 20, height = 20.

If I have:

rect1 = new Rectantle(0,0,20,20);

rect 2= new Rectantle(20,0,20,20);

I'll have width = 40, height = 20.

This is a very simple sample; I should know the size of a DirectedTreeLayout with lots of nodes and levels.

Thank you,
Ivan

[Swarnesh Krishna Kumar]

Hi Ivan,
Thanks for using Syncfusion products.
We are glad to inform that we have created a simple sample to achieve your requirement.

how can I get the actual size of my diagram? For example: rect = new Rectantle(0,0,20,20); I want to get the size of the diagram, so, width = 20, height = 20. If I have: rect1 = new Rectantle(0,0,20,20); rect 2= new Rectantle(20,0,20,20); I'll have width = 40, height = 20. This is a very simple sample;

We suggest you to get the size of the diagram by Diagram.Model.LogicalSize.Width and Diagram.Model.LogicalSize.Height. Here is the code snippet: [C#] //Finding the size of the diagram SizeF DiagramSize = new SizeF(diagram1.Model.LogicalSize.Width, diagram1.Model.LogicalSize.Height);

I should know the size of a DirectedTreeLayout with lots of nodes and levels.

We suggest you to get the size of the layout by passing the Layoutmanager.Model.Nodes and the MeasureUnit in Diagram.Controller.GetBoundingRect property. Here is the code snippet: [C#] DirectedTreeLayoutManager dtlm = new DirectedTreeLayoutManager(this.diagram1.Model, 0, 50, 60); RectangleF Rect = new RectangleF(); //Finding the size of the layout Rect=this.diagram1.Controller.GetBoundingRect(dtlm.Model.Nodes, MeasureUnits.Pixel); SizeF LayoutSize = new SizeF(Rect.Width, Rect.Height); Here is the Sample: Sample

Please let us know if any concerns.
Regards,
Swarnesh K