Finding externally added row with data criteria, make it visible and selected - focused

Question

Hi,We are adding externaly a new data object in the  underline data list,  We update the DataGridSource buildGridRows();notifyListeners(); We find in DataGridRows with a For loop, the position of the new row applying data criteria (the key on the cells). (it can be sorted or not).  Is there a better way ?

We can't make the specific row visible and selected Using any of those   (selection mode is single   -  no paging)//  userGridController.selectedIndex= pos;  userGridController.selectedRow = _usersDataSource.dataGridRows[pos];

// userGridController.scrollToRow(pos.toDouble());

What is the best way to do the steps 2 ,3,4thank you

Tamilarasan Paranthaman · Accepted Answer

Hi Stefan,As per your requirement, you can achieve
that using the DataGridController. After adding the DataGrid row into
the underline collection call the notifyListeners from the DataGridSource
class, find the added row index from the DataGridSource.effectiveRows property.
Then, assign that index to the DataGridController.selectedIndex for
selecting the current added row and using the DataGridController.scrollToRow
property for scrolling into the added row. We have prepared a sample for
that. Please check the following sample and code snippet.

@override
    Widget build(BuildContext context) {
      return Scaffold(
        appBar: AppBar(
          title: const Text('Syncfusion Flutter
  DataGrid'),
        ),
        body: Column(
          children: [
            Card(
              margin: const EdgeInsets.all(20),
              child: ElevatedButton(
                  onPressed: (() {
                    DataGridRow dataGridRow =
  DataGridRow(cells: [
                      DataGridCell(
                          columnName: 'ID',
  value: random.nextInt(2000)),
                      const
  DataGridCell(
                          columnName: 'Name',
  value: 'Jack'),
                      const
  DataGridCell(
                          columnName:
  'Designation', value: 'C.E.O'),
                      const
  DataGridCell(columnName: 'Salary', value: 30000),
                    ]);
                    _employeeDataSource.datagridRows.add(dataGridRow);
   
                    _employeeDataSource.updateDataGridSource();
   
                    int index =
                       
  _employeeDataSource.effectiveRows.indexOf(dataGridRow);
   
                    dataGridController.selectedIndex = index;
   
                    dataGridController
                       
  .scrollToRow(dataGridController.selectedIndex.toDouble());
                  }),
                  child: const Text('Add
  Row')),
            ),
            Expanded(
                child: SfDataGrid(
                    source:
  _employeeDataSource,
                    controller:
  dataGridController,
                    columnWidthMode:
  ColumnWidthMode.fill,
                    selectionMode:
  SelectionMode.single,
                    columns: getColumns)),
          ],
        ),
      );
    }
  }
   
  In DataGridSource   class:
   
  class
  EmployeeDataSource extends DataGridSource {
   
  …
   
    void updateDataGridSource() {
      notifyListeners();
    }
  }

Sample Link: https://www.syncfusion.com/downloads/support/directtrac/general/ze/sample425532589
We hope this
helps. Please let us know if you need any further assistance with this.Regards,TamilarasanAttachment: Demo_f2e78386.zip

Stefan Tsalapatis · Answer

Thanks