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Update node label position

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96737 Oct 1,2010 11:15 AM Oct 5,2010 09:13 AM Windows Forms 1
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Tags: Diagram
Witold Slirz
Asked On October 1, 2010 11:15 AM

Hi,
Im using this code to calculate node's label position:

label.Position = Position.Custom;
label.OffsetX = node.Size.Width / 2;
label.OffsetY = node.Size.Height + 20;

How to recalculate label position automatically when user resize node?


Pandi Murugan A [Syncfusion]
Replied On October 5, 2010 09:13 AM

Hi Witold,

Thank you for your interest in Syncfusion Products.

We suggest you to use Diagram DocumentEventSink's SizeChanged event to update the Node's Label position. Please refer the below code snippet.


[C#]
public Form1()
{
InitializeComponent();
((DocumentEventSink)diagram1.Model.EventSink).SizeChanged+=new SizeChangedEventHandler(Form1_SizeChanged);
}

void Form1_SizeChanged(SizeChangedEventArgs evtArgs)
{
//update the label position here
PathNode node = evtArgs.NodeAffected as PathNode;
if (node.Labels.Count > 0)
if (node.Labels[0] != null)
{
node.Labels[0].OffsetX = node.Size.Width / 2;
node.Labels[0].OffsetY = node.Size.Height + 20;
}
}


For your convenience, we have created a simple sample and the same can be downloaded from below link.

LabelPosition648179222.zip

Please let me know if you have any concerns.

Regards,
Pandi Murugan A



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