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Update node label position

Thread ID:





96737 Oct 1,2010 11:15 AM Oct 5,2010 09:13 AM Windows Forms 1
Tags: Diagram
Witold Slirz
Asked On October 1, 2010 11:15 AM

Im using this code to calculate node's label position:

label.Position = Position.Custom;
label.OffsetX = node.Size.Width / 2;
label.OffsetY = node.Size.Height + 20;

How to recalculate label position automatically when user resize node?

Pandi Murugan A [Syncfusion]
Replied On October 5, 2010 09:13 AM

Hi Witold,

Thank you for your interest in Syncfusion Products.

We suggest you to use Diagram DocumentEventSink's SizeChanged event to update the Node's Label position. Please refer the below code snippet.

public Form1()
((DocumentEventSink)diagram1.Model.EventSink).SizeChanged+=new SizeChangedEventHandler(Form1_SizeChanged);

void Form1_SizeChanged(SizeChangedEventArgs evtArgs)
//update the label position here
PathNode node = evtArgs.NodeAffected as PathNode;
if (node.Labels.Count > 0)
if (node.Labels[0] != null)
node.Labels[0].OffsetX = node.Size.Width / 2;
node.Labels[0].OffsetY = node.Size.Height + 20;

For your convenience, we have created a simple sample and the same can be downloaded from below link.


Please let me know if you have any concerns.

Pandi Murugan A


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