How to detect the validation of a filter with GridOffice2007Filter?

[Raphael]

Hello,

I am working with a GridGroupingControl and a GridOffice2007Filter.

The filter is associated to the grid, so I have a red icon at corner bottom right of ColHeaders.

Because my GridGroupingControl is large, I would like the user can visually know the ColHeaders which he filtered.

That is why I would like to detect when the button "OK" in my GridOffice2007Filter is pressed, in order to change the backcolor of the ColHeader of the column filtered.

Could you help me please?

Thanks in advance for your future response.

Sincerely,

Raphaël.

[Jisha Joy]

Hi Raphael,

You could achieve the desired behavior by handling the RecordFilters.Changed and TableControlPrepareViewStyleInfo events.

this.gridGroupingControl1.TableDescriptor.RecordFilters.Changed += new Syncfusion.Collections.ListPropertyChangedEventHandler(RecordFilters_Changed);
            this.gridGroupingControl1.TableControlPrepareViewStyleInfo += new GridTableControlPrepareViewStyleInfoEventHandler(gridGroupingControl1_TableControlPrepareViewStyleInfo);
		

        void gridGroupingControl1_TableControlPrepareViewStyleInfo(object sender, GridTableControlPrepareViewStyleInfoEventArgs e)
        {
            GridCurrentCell cc = this.gridGroupingControl1.TableControl.CurrentCell;
            GridTableCellStyleInfo style = e.Inner.Style as GridTableCellStyleInfo;
            if (style.TableCellIdentity.Column != null && ht.Contains(style.TableCellIdentity.Column.Name)
                && (style.TableCellIdentity.TableCellType == GridTableCellType.ColumnHeaderCell ))
            {
                e.Inner.Style.Themed = false;
                e.Inner.Style.BackColor = Color.Red;
            }

        }
        Hashtable ht = new Hashtable();
        void RecordFilters_Changed(object sender, Syncfusion.Collections.ListPropertyChangedEventArgs e)
        {
           
            RecordFilterDescriptor dex = e.Item as RecordFilterDescriptor;
            ht.Add(dex.FieldDescriptor.Name, dex.FieldDescriptor.Name);
      

        }

Regards,
Jisha

[Raphael]

Hi!

Thank you very much, it works!

Have a nice day.

Sincerely,

Raphaël.

[Jisha Joy]

Hi Raphaël,

Thank you for your update.

Regards,
Jisha