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Enable / Disable Docking at runtime

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53632 Dec 18,2006 04:17 AM Dec 18,2006 09:58 AM Windows Forms 1
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Administrator [Syncfusion]
Asked On December 18, 2006 04:17 AM

Hi,

we have a form with three docked controls (all three controls are docked on the left side).

Now I want to disable (hide) all three controls with a click on the menu. Furthermore I want to bring them back (docked again on the left side) with another click on the menu.

How can I solve this - any help would be great?


Thanks in advance,

Chris

Murugan [Syncfusion]
Replied On December 18, 2006 09:58 AM

Hi Chris,

Thanks for choosing Syncfusion products.

DockingManager.SetDockVisibility method shows/hides the docked control and keeps the DockingStyle also.

To show a docked control DockingManager.SetDockVisibility( ctrl , true );

To hide a docked control DockingManager.SetDockVisibility( ctrl , false );

Here is the code snippet for your query:

private void barItem1_Click(object sender, EventArgs e)
{
if (this.barItem1.Checked)
{
this.dockingManager1.SetDockVisibility(this.panel1, false);
this.dockingManager1.SetDockVisibility(this.panel2, false);
this.dockingManager1.SetDockVisibility(this.panel3, false);
this.barItem1.Checked = false;
}
else
{
this.dockingManager1.SetDockVisibility(this.panel1, true);
this.dockingManager1.SetDockVisibility(this.panel2, true);
this.dockingManager1.SetDockVisibility(this.panel3, true);
this.barItem1.Checked = true ;
}
}

Please use this code and let me know if the issue is resolved.

Regards,
Murugan P.S

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