Can I map Grid cell to row in DataSource?

Looking for a way to get to the exact row in the DataTable, give the row index in the Grid. I am using the GridDataBoundGrid and am binding to a hierarchical DataSet. Is there a way to do this? Tx, curt

5 Replies

AD Administrator Syncfusion Team March 26, 2003 11:30 PM UTC

Have you tried this.gridDataBoundGrid1.Binder.RowIndexToListManagerPosition to see if that will give you the value you want?


AU Andy Ullman March 27, 2003 03:33 PM UTC

Hey Curt! I'm working on the same issue. According to another post, Binder.RowIndexToListManagerPosition will work until the datagrid ordering changes (through a sort, on new rows added), then the index into Rows doesn't match up anymore. Instead, you should index through Table["table"].DefaultView.Item[Binder.RowIndexToListManagerPosition] I can't test this though - for some reason, the compiler is complaining that Item is not a property of a DataView. The docs clearly state that it is (unless I'm missing something stupid). I'm going to install .net framwork sp2 and see if that fixes it. Andy > Have you tried > > this.gridDataBoundGrid1.Binder.RowIndexToListManagerPosition > > to see if that will give you the value you want?


AU Andy Ullman March 27, 2003 03:58 PM UTC

Now I see my mistake. You access it like this: ds.Tables["table"].DefaultView[Binder.RowIndexToListManagerPosition] Compiles but still not working for me. ANdy


SG Sean Greer March 27, 2003 04:10 PM UTC

Does this not work? int nRowIndex = grid.Binder.CurrentRowIndex; int nListIndex = grid.Binder.RowIndexToListManagerPosition(nRowIndex); DataRowView drv = ds.YourTable.DefaultView[nListIndex];


AU Andy Ullman March 28, 2003 04:57 PM UTC

It was not giving me the correct row in the datatable when the datagrid was sorted. I studied a working example from another post and found one difference with my code - in my code, I set datagrid.datasource equal to the dataset, and datagrid.datamember = "table name". In the working example, datagrid.datasource is set to the datatable (the object). I made that change in my code and now it works. Looks like a bug. I'm using grid ver 1.5.2. Andy

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