Set gridrows to a model property list

Question

Hey!I have a ViewModel which has a List property:The ViewModel: The property ViewModel: I managed to load the subitems to a grid and I would like to send the selected rows to the controller.  Is it possible anyhow? I used to use for this kind of problems the name html attribute like name="Something[i].Anything"Please let me know if you need more information or the source code. Thank you in advance!Ferenc

Ferenc · Answer

In the meantime I've found a workaround to my problem. I've created templates for the grid columns with the proper input and name attributes:

It works properly but please if you know an easier / nicer method let me know, thanks! :)

Joseph Christ Nithin Issack · Answer

Hi Ferenc,  Greetings from the Syncfusion support.  Based on your requirement, you want to get the
selected rows in the controller. You can get the selected row using the method
‘getSelectedRows’  which returns the row elements or if you want to
access the data of the selected rows you can use the `getSelectedRecords`.API: https://ej2.syncfusion.com/documentation/api/grid/#getselectedrecords
https://ej2.syncfusion.com/documentation/api/grid/#getselectedrowsIf the above does not satisfy your requirement, please share
the details so that we may be able to assist you in a better way.
 You have used templates
     for the columns, please ensure that you have used template only for
     getting the data in the selected rows?
 Please explain your
     requirement in detail.
 Please share a video
     demo for your requirement.
 Please share a simple
     sample for further validation.
 Please share the
     Syncfusion package version you are using.
Please get back to us for further details.Regards,Joseph I.