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Connector - how to determine double click on label?

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109710 Jul 1,2013 03:41 AM Jul 4,2013 01:22 AM Windows Forms 1
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Tags: Diagram
Klaudiusz Bryja
Asked On July 1, 2013 03:41 AM

Hi,

Is it possible to determine double click on label element on connector (http://help.syncfusion.com/cr/windows%20forms/diagram)? We want to start action on this event. How to achive this?

 

Best regards,

Klaudiusz


Amsath Ali M [Syncfusion]
Replied On July 4, 2013 01:22 AM

Hi Klaudiusz,

 

Thanks for using Syncfusion products.

 

We suggest you to use the Diagram.EventSink’s NodeDoubleClick’ event and the below code to determine whether the mouse is double clicked on label. Please refer the below code snippet to achieve your requirement.

 

Here is the code:

[C#]

diagram1.EventSink.NodeDoubleClick += new NodeMouseEventHandler(EventSink_NodeDoubleClick);

void EventSink_NodeDoubleClick(NodeMouseEventArgs evtArgs)

        {

            PathNode node = evtArgs.Node as PathNode;

            Syncfusion.Windows.Forms.Diagram.Label lbl = node.Labels[0];

            PointF lblPosition = node.ConvertToModelCoordinates(lbl.GetPosition());

            RectangleF lblBounds = new RectangleF(new PointF(lblPosition.X - lbl.Size.Width / 2, lblPosition.Y - lbl.Size.Height / 2), lbl.Size);

            if (lblBounds.Contains(diagram1.Controller.MouseLocation))

                MessageBox.Show("success");

        }

 

Please refer the below attached sample and let us know if you have any queries.

 

Regards,

Amsath Ali. M



F109710_aafddf1.zip

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