We use cookies to give you the best experience on our website. If you continue to browse, then you agree to our privacy policy and cookie policy.
Unfortunately, activation email could not send to your email. Please try again.

How to create Grid instance using @ViewChild in Angular 2

We can access the Grid instance in Angular2 component by using @ViewChild decorator and pass the template reference name as parameter to the @ViewChild decorator.

Template

 

TypeScript

import {Component, ViewEncapsulation,ViewChild} from '@angular/core';

import {CommonModule} from "@angular/common";

import {EJComponents} from './ej/core';

 

@Component({

   selector: 'ej-app',

  templateUrl: 'app/app.component.html',

})

 

export class AppComponent {

 

public gridData = ej.DataManager({

    url: "http://mvc.syncfusion.com/Services/Northwnd.svc/Employees"

});

 

@ViewChild('grid') Grid: EJComponents<any, any>;

ngAfterViewInit(){

 

    this.Grid.widget.selectRows(2)// call the selectrows API for selecting the rows

}

 

}

 

The following screenshot display the selected rows based on the value.

Figure 1: Output

Article ID: Published Date: Last Revised Date: Platform: Control:
7527 03/01/2017 03/01/2017 JavaScript ejGrid
Tags:
Did you find this information helpful?
Add Comment
You must log in to leave a comment

You are using an outdated version of Internet Explorer that may not display all features of this and other websites. Upgrade to Internet Explorer 8 or newer for a better experience.